- - AGRICULTURE CORE CURRICULUM - - (CLF2000) Advanced Core Cluster: AGRICULTURE MECHANICS (CLF2900) Unit Title: WORK AND POWER ____________________________________________________________________________ (CLF2911) Topic: WORK AND POWER Time Year(s) FORMULAS 3 Hours 1 / 2 / 3 / 4 ____________________________________________________________________________ Topic Objectives: Upon completion of this lesson the student will be able to: Learning Outcome #: (S-2) - Demonstrate knowledge of energy, force, pressure, work, and power, using applications of levers, gears, pulleys, and shafts. (T-3) - Demonstrate knowledge of the transmission of power, using chains, belts, gears, and shafts. Special Materials and Equipment: None References: Jacobs, C. O., & Harrell, W. R. (1983). AGRICULTURAL POWER AND MACHINERY. New York: McGraw-Hill. Smith, H. P., & Lambert, H. W. (1976). FARM MACHINERY AND EQUIPMENT. (6th ed.) New York: McGraw-Hill. Evaluation: Quiz by instructor and evaluation in discussion and lab work. TOPIC PRESENTATION: WORK AND POWER FORMULAS A. Formulas 1. Work a. Work (ft X lbs) = force applied (pounds) X distance moved (feet) b. Electrical Energy 1) Work is moving electrical charges against resistance 2) E = I X R Where, E = electrical energy (watt-hours or kilowatt-hours) I = electrical current (amperes) R = electrical resistance (ohms) c. Heat Energy 1) Q = (M)(C)(TF - TI) Where, Q = Amount of heat required to heat up a given amount of matter (BTU's) M = Weight of the matter to be heated (lbs.) C = Constant (equals 1 for water) TF = Desired final temperature of the matter TI = Initial temperature of the matter d. Pump Energy 1) The energy to pump irrigation water is given by the formula: KWH/ACFT = (1.024)(H)/E Where, KWH/ACFT = pump energy in kilowatt hours per acre foot of water pumped H = total lift of the pump in feet E = pump efficiency as a decimal 2. Power a. Fluid 1) HHP = (F)(P)/1714 Where, HHP = Hydraulic horsepower of pumped hydraulic oil F = Flow of the hydraulic oil pumped in gallons per minute P = Pressure of the pumped oil in pounds per square inch b. Engine 1) Drawbar Horsepower DBHP = (D)(W)(S)/375 Where, DBHP = Drawbar horsepower D = Draft (lbs) = pull exerted on the implement by the tractor (see chart on following page) W = Operating width of the implement (feet) S = Speed of the tractor (mph) 2) PTO Horsepower (2-WD tractors ONLY) PTOHP = (K)(DBHP) Where, DBHP = Drawbar horsepower as calculated above K = factor depending upon soil condition, tire type, etc. (see following page for typical values) 3) Rotary PTO Horsepower RPTOHP = (T)(R)/5252 Where, RPTOHP = PTO horsepower from the PTO shaft T = Torque (lb-ft) provided by the PTO shaft R = Speed of rotation of the PTO shaft in revolutions per minute UNIT DRAFT REQUIREMENTS OF FARM IMPLEMENTS Implement Operation Unit Draft (UD)* Moldboard Plow light soil 500 lbs/ft medium soil 800 lbs/ft heavy soil ll00 lbs/ft Lister light soil 400 lbs/ft medium soil 600 lbs/ft heavy soil 800 lbs/ft Field cultivator 290 lbs/ft Light disc harrow 250 lbs/ft Medium disc harrow 600 lbs/ft Heavy disc harrow l000 lbs/ft Row crop planter l50 lbs/ft Grain drill 70 lbs/ft Spike tooth harrow 40 lbs/ft Roller l00 lbs/ft Subsoiler light soil 840 lbs per shank per foot of depth medium soil 1200 lbs per shank per foot of depth heavy soil 1920 lbs per shank per foot of depth Landplane 500 lbs/ft Chisel plow 500 lbs/ft Spring-tooth harrow l90 lbs/ft *pounds per foot of width unless otherwise noted. _____________________________________________________________________________ K FACTORS FOR 2-WHEEL DRIVE TRACTORS Soil Conditon K-Factor Concrete l.l4 Firm, untilled soil l.50 Tilled, reasonably firm soil l.80 Freshly plowed soft soil 2.10 c. Electrical 1) P= I X E X pf Where, P = power in watts E = electrical energy (watt-hours or kilowatt-hours = I X R pf = power factor encountered in AC power with inductive and capacitive loads, I = current flow (amperes) 2) For DC applications P = I X E P = I X (I X R) 2 P= I X R 3. Pressure a. Pressure (psi) is the force per unit area b. Formula: 1) P = F divided by A Where, P = pressure (psi) F = force (lbs) A = area (square inches) 4. Torque a. Torque is a twisting force applied about the center of rotation or fulcrum. b. Formula: Tq. (lbs. X ft) = Force (lbs.) X Distance (ft) or, Tq. (lbs. X in) = Force (lbs.) X Distance (in) 5. Energy Efficiencies a. Mechanical Efficiency - takes into account all factors that keep horsepower away from an engine, including friction H.P. loss to find mechanical efficiency: Brake H.P. ________________ X 100 = Mechanical Efficiency (%) Indicated H.P. b. Volumetric Efficiency - the limiting factor in an engine's maximum torque output. To find volumetric efficiency: Actual Air Inducted into Engine (cu. in.) _____________________________ X 100 = Volumetric Efficiency (%) Engine Cubic Inch Displacement c. Brake Thermal Efficiency - brake horsepower expressed in BTU's, divided by the fuel heat input (BTU's), times 100 Engine H.P. X 2545 (BTU's) __________________________ X 100 = B.T.E.(%) Fuel Burned / Hr.(BTU's) 7/23/91 YNJ/JWR/sg #%&C